How do you multiply #4x ^ { 3} y ^ { 2} \cdot 4x ^ { 3} y ^ { 2}#?

1 Answer
Apr 12, 2017

See the entire solution process below:

Explanation:

First, rewrite this expression as:

#(4 * 4)(x^3x^3)(y^2y^2) = 16(x^3x^3)(y^2y^2)#

Now, use this rule of exponents to multiply the #x# and #y# terms:

#x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#

#16(x^color(red)(3) xx x^color(blue)(3))(y^color(red)(2) xx y^color(blue)(2)) = 16x^(color(red)(3) + color(blue)(3))y^(color(red)(2) + color(blue)(2)) = 16x^6y^4#