How do you multiply #(- 5c ^ { 8} ) \cdot 7d ^ { 7} \cdot 2c#?

1 Answer
May 17, 2017

See a solution process below:

Explanation:

First, rewrite the expression as:

#(-5 * 7 * 2)(c^8 * c)d^7 => -70(c^8 * c)d^7#

Now. use these two rules of exponents to multiply the #c# terms:

#a = a^color(blue)(1)# and #x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#

#-70(c^color(red)(8) * c^color(blue)(1))d^7 => -70(c^(color(red)(8)+color(blue)(1)))d^7 => -70c^9d^7#