How do you multiply #(5x + 1) \cdot ( 6x + 3)#?

2 Answers
Mahek ☮
Mar 6, 2018

#color(magenta)(=30x^2+21x+3#

Explanation:

#(5x+1)xx(6x+3)#

[Opening the brackets]

#=5x(6x+3)+1(6x+3)#

#=30x^2+15x+6x+3#

#color(magenta)(=30x^2+21x+3#

~Hope this helps! :)

Jim G.
Mar 6, 2018

#30x^2+21x+3#

Explanation:

#"each term in the second factor is multiplied by each term"#
#"in the first factor"#

#rArr(color(red)(5x+1))(6x+3)#

#=color(red)(5x)(6x+3)color(red)(+1)(6x+3)#

#=(color(red)(5x)xx6x)+(color(red)(5x)xx3)+(color(red)(1)xx6x)+(color(red)(1)xx3)#

#=30x^2color(blue)(+15x)color(blue)(+6x)+3larrcolor(blue)"collect like terms"#

#=30x^2+21x+3#

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