How do you multiply (5x^2)/(3y) * (9xy)/20 *( 4y^2)/(3x^2)5x23y9xy204y23x2?

1 Answer
Sep 17, 2015

The answer is xy^2xy2.

Explanation:

(5x^2)/(3y) * (9xy)/(20) *(4y^2)/(3x^2)5x23y9xy204y23x2

Multiply the numerators and denominators.

(5x^2*9xy*4y^2)/(3y*20*3x^2)=5x29xy4y23y203x2=

(180x^3y^3)/(180x^2y)180x3y3180x2y

Simplify.

(cancel(180)x^3y^3)/(cancel(180)x^2y)=

(x^3y^3)/(x^2y)

Apply the exponent rule a^m/a^n=a^(m-n)

x^(3-2)y^(3-1)=

xy^2