How do you multiply #(5x^2)/(3y) * (9xy)/20 *( 4y^2)/(3x^2)#?

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Answer 1 · 2015-09-17T23:00:49

The answer is #xy^2#.

#(5x^2)/(3y) * (9xy)/(20) *(4y^2)/(3x^2)#

Multiply the numerators and denominators.

#(5x^2*9xy*4y^2)/(3y*20*3x^2)=#

#(180x^3y^3)/(180x^2y)#

Simplify.

#(cancel(180)x^3y^3)/(cancel(180)x^2y)=#

#(x^3y^3)/(x^2y)#

Apply the exponent rule #a^m/a^n=a^(m-n)#

#x^(3-2)y^(3-1)=#

#xy^2#