How do you multiply #5y ( 9y - y ^ { 2} )#?

1 Answer
EZ as pi
Jan 26, 2018

#45y^2 -5y^3#

Explanation:

Use the distributive law to multiply #color(blue)(5y)# in front of the bracket by BOTH terms inside the bracket.

#color(blue)(5y)(9y-y^2)#

#= color(blue)(5y) xx9y" "-" "color(blue)(5y) xxy^2#

#= 45y^2 " "-" "5y^3#

These are unlike terms and cannot be simplified further,

#45y^2 -5y^3#

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