How do you multiply #(6x^2-54x)/(x-9)*(7x)/(6x)# and state the excluded values?
Multiply numerators together to find new numerator, and multiply denominators to find new denominator. 9 and 0 are excluded, as each one sets a denominator equal to 0.
The excluded values will be those wherein the denominator is 0. This is the case for any situation where either denominator of the factors would be 0. In this case, those would be
We multiply these expressions by multiplying the numerators and denominators separately. The product of the numerators will be the new numerator, and the product of the denominators will be the new denominator.
We can factor out both an
Note that now the numerator is a multiple of the denominator...
And for any