How do you multiply #(7-2sqrt3)^2#?

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Answer 1 · 2015-06-07T08:02:52

Problem: Multiply #(7-2sqrt 3)^2#

This is an example of the Square of a Difference, in which

#(a-b)^2=a^2-2ab+b^2#.

#a=7#
#b=2sqrt3#

#(7-2sqrt 3)^2=7^2-2xx7xx2sqrt3+(2sqrt3)^2# =

#49-28sqrt 3+(4xx3)# =

#49-28sqrt 3+12# =

#61-28sqrt 3#