How do you multiply #(9x - 3) ( - 6x + 8)#?

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Answer 1 · 2017-02-21T14:03:23

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(9x) - color(red)(3))(color(blue)(-6x) + color(blue)(8))# becomes:

#-(color(red)(9x) xx color(blue)(6x)) + (color(red)(9x) xx color(blue)(8)) + (color(red)(3) xx color(blue)(6x)) - (color(red)(3) xx color(blue)(8))#

#-54x^2 + 72x + 18x - 24#

We can now combine like terms:

#-54x^2 + (72 + 18)x - 24#

#-54x^2 + 90x - 24#