How do you multiply and simplify #\frac { 2n ^ { - 1} \cdot 10n ^ { - 1} \cdot 8n ^ { 5} } { 10n }#?

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Answer 1 · 2018-07-13T02:46:53

#16n^2#

Looking at the numerator
#2n^(-1)*10n^(-1)*8n^5#

=#2/n*10/n*8n^5#

=#(160n^5)/n^2#

=#160n^3#

Therefore, #(2n^(-1)*10n^(-1)*8n^5)/(10n)# becomes #(160n^3)/(10n)#

#(160n^3)/(10n)#

=#16n^2#