How do you multiply and simplify \frac { ( 8a ) ^ { 3} * ( 2a ^ { 1} c ^ { 2} ) ^ { 3} } { 2a ^ { 2} b ^ { 2} c ^ { 3} }(8a)3(2a1c2)32a2b2c3?

1 Answer
Feb 2, 2017

(2^11a^4c^2)/b^2211a4c2b2

Explanation:

((8a)^3*(2a^1c^2)^3)/(2a^2b^2c^3(8a)3(2a1c2)32a2b2c3

:.=((2^3a)^3*2^3a^3c^6)/(2a^2b^2c^3

:.=(2^9a^3*2^3a^3c^6)/(2^1a^2b^2c^3

:.=(2^9a^3*2^2a^1c^2)/b^2

:.=(2^(9+2)a^(3+1)c^2)/b^2

:.=(2^11a^4c^2)/b^2