Question

How do you multiply and simplify `\frac { x ^ { 2} + 3x } { 7} \cdot \frac { 15} { 3x + 9}`?

Answer 1

`= (5x)/7`

Explanation:

Factorise wherever you can first:

`(x(x+3))/7 xx 15/(3(x+3))`

`=(x(cancel(x+3)))/7 xx cancel15^5/(cancel3cancel((x+3))`

`= (5x)/7`