How do you multiply #\frac { 7x ^ { 2} y ^ { 3} \cdot 2x y ^ { 2} } { 7x ^ { 2} }#?

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Answer 1 · 2016-11-30T01:52:52

#2xy^5#

To answer this, I'm going to group things a bit differently:

Here's the original:

#(7x^2y^3xx2xy^2)/(7x^2)#

Now let's regroup to cancel out the denominator:

#(7x^2(y^3)2xy^2)/(7x^2)#

#(7x^2)/(7x^2)(y^3)2xy^2#

#(1)(y^3)2xy^2#

The denominator is gone, so now let's combine the remaining terms:

#2xy^2y^3#

#2xy^(2+3)#

#2xy^5#