Question

How do you multiply `sqrt2(3sqrt14 - sqrt7)`?

Answer 1

`6sqrt7-sqrt14`

Explanation:

Multiply `sqrt2` by each term in the parentheses

`sqrt2(3sqrt14-sqrt7)`

`sqrt2*3sqrt14-sqrt2*sqrt7`

`3sqrt28-sqrt14 rarr 3sqrt28` can be simplified

`3sqrt28=3sqrt4*sqrt7 rarr` `4` is a perfect square

`6*sqrt7=6sqrt7=3sqrt28`

`6sqrt7-sqrt14`