How do you multiply #sqrt2(3sqrt14 - sqrt7)#?

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Answer 1 · 2018-03-27T00:33:25

#6sqrt7-sqrt14#

Multiply #sqrt2# by each term in the parentheses

#sqrt2(3sqrt14-sqrt7)#

#sqrt2*3sqrt14-sqrt2*sqrt7#

#3sqrt28-sqrt14 rarr 3sqrt28# can be simplified

#3sqrt28=3sqrt4*sqrt7 rarr# #4# is a perfect square

#6*sqrt7=6sqrt7=3sqrt28#

#6sqrt7-sqrt14#