How do you multiply #(x ^ { 0} y ^ { 4} z ^ { 0} ) ^ { 3} \cdot 2x ^ { 0} y ^ { 2} z ^ { - 4}#?

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Answer 1 · 2017-12-19T05:09:48

#2y^14z^-4#

Let's first see that we have terms with zero as an exponent. Remember that the rule is #x^0=1#. So let's first simplify:

#(x^0y^4z^0)^3xx2x^0y^2z^-4#

#(y^4)^3xx2y^2z^-4#

Now let's work on the #(y^4)^3# term. We can use the rule #(x^a)^b=x^(ab)#:

#y^12xx2y^2z^-4#

And now let's see we have two #y# terms and we can use the rule #x^a xx x^b = x^(a+b)#:

#2y^14z^-4#