How do you multiply #x^ { 2} y ^ { 4} \cdot x ^ { 5} y ^ { 12}#?

2 Answers
Dec 30, 2016

See the explanation below for how to multiply this expression:

Explanation:

First you can rearrange this expression as follows:

#x^2x^5y^4y^12#

Next we can use the following rule for exponents to multiply the #x# and #y# terms separately:

#color(red)(x^ax^b = x^(a+b))#

#x^2x^5y^4y^12 = x^(2+5)y^(4+12) =#

#x^7y^16#

Dec 30, 2016

The result is # x^7*y^16#

Explanation:

Since multiplication is commutative, you can change the order of the terms. Write it as

#x^2*x^5*y^4*y^12#

Now, combine the powers that have the same base (#x# or #y#) by adding the exponents:

#x^(2+5)*y^(4+12) = x^7*y^16#

That is the final result.

Here's why the "add the exponents" rule works:

#x^2*x^5# is the same as #(x*x)*(x*x*x*x*x)#, which is simply #x^7#