How do you multiply $(x + 3) (x - 2) (x + 1) (2 x + 3)$ $(x + 3) ( x - 2) ( x + 1) ( 2x + 3)$ ?

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Answer 1 · 2018-04-08T08:48:40

$2 x^{4} + 7 x^{3} - 4 x^{2} - 27 x - 18$ $2x^4+7x^3-4x^2-27x-18$

$(x + 3) (x - 2)$ $(x+3)(x-2)$ = $x^{2} - 2 x + 3 x - 6$ $x^2-2x+3x-6$ = $x^{2} + x - 6$ $x^2+x-6$

( $x^{2} + x - 6$ $x^2+x-6$ )( $x + 1$ $x+1$ ) = $x^{3} + x^{2} + x^{2} + x - 6 x - 6$ $x^3+x^2+x^2+x-6x-6$

= $x^{3} + 2 x^{2} - 5 x - 6$ $x^3+2x^2-5x-6$

( $x^{3} + 2 x^{2} - 5 x - 6$ $x^3+2x^2-5x-6$ )(2x+3)

= $2 x^{4} + 3 x^{3} + 4 x^{3} + 6 x^{2} - 10 x^{2} - 15 x - 12 x - 18$ $2x^4+3x^3+4x^3+6x^2-10x^2-15x-12x-18$

= $2 x^{4} + 7 x^{3} - 4 x^{2} - 27 x - 18$ $2x^4+7x^3-4x^2-27x-18$

How do you multiply (x+3)(x−2)(x+1)(2x+3)(x + 3) ( x - 2) ( x + 1) ( 2x + 3)?