How do you multiply #(z x ^ { 4} y ^ { 2} ) \cdot ( x ^ { 2} y ^ { 4} z ^ { 3} ) ^ { 2} \cdot ( x ^ { - 1} z ^ { - 1} ) ^ { - 1}#?

1 Answer
Mar 3, 2018

#x^9.y^10.z^8#

Explanation:

#zx^4.y^2.x^(2.2).y^(4.2).z^(3.2)(x^-1.z^-1)^-1#

#zx^4.y^2.x^4.y^8.z^6(x^-1.z^-1)^-1#

#x^8.y^10.z^7(x^-1.z^-1)^-1#

#(x^8.y^10.z^7). 1/(x^-1.z^-1)^1#

#(x^8.y^10.z^7 .1) /(x^-1 z^-1)#

#x^(8-(-1)) . y^10 . z^(7-(-1))#

#x^9.y^10.z^8#