# How do you perform the operation and write the result in standard form given (13-2i)+(-5+6i)?

Sep 18, 2016

$8 + 4 i$

#### Explanation:

We have: $\left(13 - 2 i\right) + \left(- 5 + 6 i\right)$

Let's collect the like terms:

$= \left(13 + \left(- 5\right)\right) + \left(\left(- 2\right) + 6\right) i$

$= \left(13 - 5\right) + \left(6 - 2\right) i$

$= 8 + 4 i$