Question

How do you perform the operation and write the result in standard form given `(8-i)-(4-i)`?

Answer 1

Let the complex number in standard form be,

`z = a + ib` where `a` and `b` are real numbers.

Thus, for `z = a + ib = (8 - i) - (4 - i)`
`implies a + ib = 8 - i - 4 + i`
`implies a + ib = 4`

Comparing both sides,

`a = 4` and `b = 0`

Therefore, `z = 4 + 0*i` in standard form.