# How do you plot sqrt46 on the decimal number line as accurately as possible?

##### 1 Answer
Aug 11, 2018

Here's how you could do it geometrically...

#### Explanation:

Draw a circle with centre $\left(0 , \frac{45}{2}\right)$ with radius $\frac{47}{2}$.

This will pass though the points $\left(0 , - 1\right)$ and $\left(0 , 46\right)$ on the $y$ axis and the points $\left(- \sqrt{46} , 0\right)$ and $\left(\sqrt{46} , 0\right)$ on the $x$ axis.

graph{(x^2 + (y-45/2)^2 - 47^2/4)((x-sqrt(46))^2+y^2-0.01)((x+sqrt(46))^2+y^2-0.01) = 0 [-9.83, 10.17, -3.28, 6.72]}