# How do you plot #sqrt46# on the decimal number line as accurately as possible?

##### 1 Answer

Aug 11, 2018

Here's how you could do it geometrically...

#### Explanation:

Draw a circle with centre

This will pass though the points

graph{(x^2 + (y-45/2)^2 - 47^2/4)((x-sqrt(46))^2+y^2-0.01)((x+sqrt(46))^2+y^2-0.01) = 0 [-9.83, 10.17, -3.28, 6.72]}