How do you prove 1+cos2A/cos2A=tan2A/tanA?

1 Answer
Mar 16, 2018

see below

Explanation:

We have,
L.H.S=#frac{1+cos2A}(cos2A#
=#frac{2cos^2A}(cos2A#
Multiplying sinA in both numerator and denominator,
=#frac{2cos^AsinA}(cos2AsinA#
If we rearrange it,then
#frac{sin2A//cos2A}(sinA//cosA#
Whis is equal to #tan2A//tanA# {R.H.S}