How do you prove #\cos ^ { 2} x = ( 1- \sin x ) ( 1+ \sin x )#?

1 Answer
Apr 7, 2017

I tried this:

Explanation:

You can multiply the two brakets and get:
#cos^2(x)=1+cancel(sin(x))cancel(-sin(x))-sin^2(x)#
#cos^2(x)=1-sin^2(x)#
#cos^2(x)=cos^2(x)#

where #1-sin^2(x)=cos^2(x)#
because you know that:
#sin^2(x)+cos^2(x)=1#