How do you prove #csc(t)cos(t)=cot(t)#?

1 Answer
Apr 10, 2018

See explanation

Explanation:

#csc# (cosecant) is the reciprocal of sine, so it is hypotenuse over opposite side to the angle

#cos# is adjacent side to the angle over hypotenuse

#cot# is the reciprocal of tangent, so it is adjacent side to angle over opposite side to angle

Let's use #H# to represent hypotenuse, #O# to represent opposite, and #A# to represent adjacent

#H/O*A/H=cancel(H)/O*A/cancel(H)=A/O rarr# #A/O# represents cotangent