How do you prove? #Sin^3A+cos^3# = #(sinA+cosA) (1-SinA*cosA)#
1 Answer
Mar 27, 2018
Explanation:
#"note that"#
#a^3+b^3=(a+b)(a^2-ab+b^2)#
#"here "a=sinA" and "b=cosA#
#rArrsin^3A+cos^3A#
#=(sinA+cosA)(sin^2 A-sinAcosA+cos^2A)#
#[sin^2A+cos^2A=1]#
#=(sinA+cosA)(1-sinAcosA)="right side"#