Question

How do you prove `(tan)(cos)=csc`?

Answer 1

I think there is a problem with this question

Explanation:

In a rectangular triangle with sides `n,f,h` where `n=` near side, `f=` far side, and `h=`hypotenuse

`tan=f/n, cos=n/h`

So `tanxxcos=f/cancelnxxcanceln/h=f/h`

And this is the definition of `sin`, not `csc`