How do you prove that #(1/2)(ln2 - ln4 + ln3) = (1/2)ln(3/2)#?

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Gió Share
Feb 2, 2015

In the bracket with #(ln2-ln4+ln3)# you can apply the following general rules of the logarithms:

1) #lna+lnb=ln(a*b)#

2) #lna-lnb=ln(a/b)#

and you should be able to get your result.

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