How do you prove that sigma ar^k-1 at k=1 to the n terms = a(1-r^n)/1-r ??

1 Answer
Dec 15, 2015

Prove by induction (below)

Explanation:

Objective:
To prove #Sigma_(k=1)^(n) ar^(k-1) = a(1-r^n)/(1-r)#

#"----------------------------------------------------------------------------"#

Show that the equation is true for #color(black)(n=1)#

If #color(black)(n=1)#
#Sigma_(k=1)^1 ar^(k-1) = ar^0 = a = a(1-r^1)/(1-r)#

#"----------------------------------------------------------------------------"#

Show that if it is true for #color(black)(n-1)# then it is true for #color(black)(n)#

Assuming #color(red)(Sigma_(k=1)^(n-1) ar^(k-1)=a(1-r^(n-1))/(1-r))#

#Sigma_(k=1)^n ar^(k-1) = color(red)(Sigma_(k=1)^(n-1)ar^(k-1))+color(blue)(ar^(n-1))#

#color(white)("XXXXXX")= a(1-r^(n-1))/(1-r) +a(r^(n-1)(1-r))/(1-r)#

#color(white)("XXXXXX")=a(1-r^(n-1)+r^(n-1)-r^n)/(1-r)#

#color(white)("XXXXXX")=a(1-r^n)/(1-r)#

#"======================================================="#