# How do you prove that the limit of (x^2+3x)=-18 as x approaches -3 using the epsilon delta proof?

You can't. The limit is not $- 18$.
${\lim}_{x \rightarrow - 3} \left({x}^{2} + 3 x\right) = {\left(- 3\right)}^{2} + 3 \left(- 3\right) = 9 - 9 = 0$