How do you put this quadratic equation into standard form? 8v^2=12-7v

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Answer 1 · 2018-06-07T14:34:30

#8v^2 + 7v - 12 = 0#

#8v^2 = 12 - 7v#

Recall;

#av^2 + bv + c = 0 -> "Standard Form"#

#8v^2 = 12 - 7v#

Adding #7v# to both sides;

#8v^2 + 7v = 12 - 7v + 7v#

#8v^2 + 7v = 12 + 0#

#8v^2 + 7v = 12#

Subtracting #12# from both sides;

#8v^2 + 7v - 12 = 12 - 12#

#8v^2 + 7v - 12 = 0 -> "Standard Form"#