# How do you rationalize 7/(sqrt3-sqrt2)?

7$\left(\sqrt{3} + \sqrt{2}\right)$
Multiply the numerator and the denominator by $\sqrt{3} + \sqrt{2}$, that would make the denominator $\left(\sqrt{3} - \sqrt{2}\right) \left(\sqrt{3} + \sqrt{2}\right)$ =3-2= 1. The result would be $7 \left(\sqrt{3} + \sqrt{2}\right)$. That is what was required.