How do you rationalize and divide #(2+sqrt3) /(2-sqrt3)#?

1 Answer
Apr 3, 2015

Using the identity #(a+b)(a-b)=a^2 - b^2#, let's multiply and divide the fraction by #2+\sqrt{3}#. You'll notice that, when doing so, at the numerator you'll have #(2+\sqrt{3})^2#, while at the denominator you'll have #(2-\sqrt{3})(2+\sqrt{3})#, which is the formula mentioned at the beginning.

So, #(2-\sqrt{3})(2+\sqrt{3})=2^2 - (\sqrt(3))^2 = 4-3=1#.

Since the denominator is #1#, we can ignore it, and the final answer is thus #(2+\sqrt{3})^2#