# How do you rationalize the denominator 2/(sqrt[3] +sqrt[2])?

Apr 12, 2015

You can multiply and divide by $\sqrt{3} - \sqrt{2}$ to get:
$\frac{2}{\sqrt{3} + \sqrt{2}} \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}} =$
$= \frac{2 \cdot \left(\sqrt{3} - \sqrt{2}\right)}{3 - 2} = 2 \cdot \left(\sqrt{3} - \sqrt{2}\right)$