Question

How do you rationalize the denominator `2/(sqrt[3] +sqrt[2])`?

Answer 1

You can multiply and divide by `sqrt(3)-sqrt(2)` to get:
`2/(sqrt(3)+sqrt(2))(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=`
`=(2*(sqrt(3)-sqrt(2)))/(3-2)=2*(sqrt(3)-sqrt(2))`