How do you rationalize the denominator #(2+sqrt3)/(5-sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Antoine Apr 1, 2015 # (2 + sqrt(3))/(5 - sqrt(3)) = ((2 + sqrt(3))xx(5 + sqrt(3)))/((5 - sqrt(3))xx(5 + sqrt(3))# # = (10 + 5sqrt(3) + 2sqrt(3) + (sqrt(3))^2)/(25 - (sqrt(3))^2)# # = (10 + 3 + 8sqrt(3))/(25 - 3)# # = (13 + 8sqrt(3))/(22)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1936 views around the world You can reuse this answer Creative Commons License