How do you rationalize the denominator and simplify #12/root3(9)#?

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Answer 1 · 2018-04-16T21:19:06

#4root3(3)#

#12/(root3(9))#

To rationalize, multiply the expression by #root3(9^2)/root3(9^2)#:

#12/(root3(9))*root3(9^2)/root3(9^2)=#

#(12(root3(9^2)))/root3(9^3)=#

#(12(root3(81)))/9=#

#(12(root3(27*3)))/9=#

#(12*3(root3(3)))/9=#

#(36(root3(3)))/9=#

#4root3(3)#