# How do you rationalize the denominator and simplify 15/(sqrt6-1)?

$3 \left(\sqrt{6} + 1\right)$
$\frac{15}{\sqrt{6} - 1} = \frac{15 \left(\sqrt{6} + 1\right)}{\left(\sqrt{6} - 1\right) \left(\sqrt{6} + 1\right)} = \frac{15 \left(\sqrt{6} + 1\right)}{6 - 1} = 3 \left(\sqrt{6} + 1\right)$[Ans]