# How do you rationalize the denominator and simplify 2/(3-sqrt7)?

We multiply and divide with $3 + \sqrt{7}$ hence we have that
$\frac{2}{3 - \sqrt{7}} \cdot \frac{3 + \sqrt{7}}{3 - \sqrt{7}} = 2 \cdot \frac{3 + \sqrt{7}}{{3}^{2} - {\left(\sqrt{7}\right)}^{2}} = 2 \cdot \frac{3 + \sqrt{7}}{9 - 7} = 3 + \sqrt{7}$