Question

How do you rationalize the denominator and simplify `2/(sqrt[3] + sqrt[2])`?

Answer 1

Multiply the denominator and numerator with `sqrt3-sqrt2`

hence

#2*(sqrt3-sqrt2)/[(sqrt[3] + sqrt[2])*(sqrt3-sqrt2)]= 2*(sqrt3-sqrt2)/[sqrt3^2-sqrt2^2]= 2*(sqrt3-sqrt2)#