# How do you rationalize the denominator and simplify (2sqrt7 - 4sqrt2)/( 2sqrt3)?

$\frac{\sqrt{21} - 2 \cdot \sqrt{6}}{3}$
$\frac{2 \sqrt{7} - 4 \sqrt{2}}{2 \cdot \sqrt{3}} = \frac{2 \sqrt{7} - 4 \sqrt{2}}{2 \cdot \sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = 2 \frac{\sqrt{7 \cdot 3} - 2 \sqrt{2 \cdot 3}}{2 \cdot 3}$