How do you rationalize the denominator and simplify #(2sqrt7 - 4sqrt2)/( 2sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Dee Apr 17, 2017 #(sqrt(21)-2*sqrt(6))/3# Explanation: #(2sqrt(7)-4sqrt(2))/(2*sqrt(3)) =(2sqrt(7)-4sqrt(2))/(2*sqrt(3)) *sqrt(3)/sqrt(3) =2(sqrt(7*3)-2sqrt(2*3))/(2*3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1440 views around the world You can reuse this answer Creative Commons License