Question

How do you rationalize the denominator and simplify `3/(sqrt6-sqrt3)`?

Answer 1

Multiply both the numerator and the denominator by the conjugate of the denominator:

`3/(sqrt(6)-sqrt(3)) = 3/(sqrt(6)-sqrt(3)) * (sqrt(6)+sqrt(3))/(sqrt(6)+sqrt(3))`

`= (3* sqrt(3) * (sqrt(2) + 1))/(6-3)`

`= sqrt(3) * (sqrt(2) + 1)`