# How do you rationalize the denominator and simplify 3/(sqrt6-sqrt3)?

$\frac{3}{\sqrt{6} - \sqrt{3}} = \frac{3}{\sqrt{6} - \sqrt{3}} \cdot \frac{\sqrt{6} + \sqrt{3}}{\sqrt{6} + \sqrt{3}}$
$= \frac{3 \cdot \sqrt{3} \cdot \left(\sqrt{2} + 1\right)}{6 - 3}$
$= \sqrt{3} \cdot \left(\sqrt{2} + 1\right)$