How do you rationalize the denominator and simplify #4/sqrt2#?

1 Answer
Jul 24, 2016

Answer:

#2sqrt2#

Explanation:

Multiply by 1 but in the form of #1=sqrt(2)/sqrt(2)#

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Multiplying by 1 does not change the inherent value.
So multiplying by #1=sqrt2/sqrt2# changes the way it looks without changing its inherent value.
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#4/sqrt2xxsqrt2/sqrt2" " =" " (cancel(4)^2sqrt2)/(cancel(2)^1)#

#=2sqrt2#