How do you rationalize the denominator and simplify 6/(3-sqrt3)?

Jul 21, 2016

$3 + \sqrt{3}$

Explanation:

$\frac{6}{3 - \sqrt{3}}$
Multiplying both numerator and denominator by $3 + \sqrt{3}$
we get
6(3+sqrt3)/((3-sqrt3)(3+sqrt3)
OR
$6 \frac{3 + \sqrt{3}}{{3}^{2} - {\left(\sqrt{3}\right)}^{2}}$
OR
$6 \frac{3 + \sqrt{3}}{9 - 3}$
OR
$6 \frac{3 + \sqrt{3}}{6}$
OR
$3 + \sqrt{3}$