# How do you rationalize the denominator and simplify (9w^9)/root4(2Z^7)?

Feb 10, 2017

$\frac{9 {w}^{9} \sqrt[4]{8 z}}{2 {z}^{2}}$

#### Explanation:

You would multiply the terms of the fraction by the factor

$\sqrt[4]{{2}^{3} z}$

Then

(9w^9root(4)(2^3z))/(root(4)(2z^7)root(4)(2^3z)

=(9w^9root(4)(8z))/(root(4)(2^4z^8)

$= \frac{9 {w}^{9} \sqrt[4]{8 z}}{2 {z}^{2}}$