How do you rationalize the denominator and simplify #(sqrt3)/(sqrt(5c))#?

1 Answer
Jul 4, 2017

Answer:

#(sqrt(15))/(5c)#

Explanation:

#sqrt3/sqrt(5c)#

To rationalize the denominator, we need to multiply the top and bottom by #sqrt(5c)#.

#(sqrt(3) xx sqrt(5c))/(sqrt(5c) xx sqrt(5c))#

#(sqrt(15c))/(sqrt(5c)^2)#

The square root and the square cancel each other out, so we are left with

#(sqrt(15))/(5c)#