How do you rationalize the denominator and simplify #(sqrt5-sqrt3)/(sqrt5+sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer P dilip_k · Tony B Mar 30, 2016 #(sqrt5-sqrt3)/(sqrt5+sqrt3)xx(sqrt5-sqrt3)/(sqrt5-sqrt3)" "=" "(5+3-2sqrt15)/(5-3)" "=4-sqrt15# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3047 views around the world You can reuse this answer Creative Commons License
