How do you rationalize the denominator of #4/root3 9#?

1 Answer
sankarankalyanam
Apr 13, 2018

#color(purple)(=>(4 * 3^(1/3)) / 3#

Explanation:

#4 / (9)^(1/3) #

#=> 4 / ((3)^2)^(1/3) #

#=>4 / (3)^(2/3)#

#=> (4 * 3(1/3)) / (3^(2/3) * 3(1/3)), " Multiply & divide by " 3^(1/3)#

#(4 * 3(1/3)) / (3^(2/3 +1/3))#

#color(purple)(=>(4 * 3^(1/3)) / 3#

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