How do you rationalize the denominator of 5 over square root of 3?

1 Answer
Oct 12, 2015

Answer:

#{5sqrt(3)}/3#

Explanation:

To razionalize means to get rid of roots at the denominator. Since #sqrt(a) * sqrt(a) = (sqrt(a))^2 = a#, then we can multiply our fraction by #1#, so that we won't change its value, but we will write #1# in a smart form, in this case #sqrt(3)/sqrt(3)#. Doing the multiplication, we get

#5/sqrt(3) * sqrt(3)/sqrt(3) = {5sqrt(3)}/{sqrt(3)*sqrt(3)} = {5sqrt(3)}/3#.