# How do you rationalize the denominator of sqrt(7/8)?

Apr 16, 2018

(√14)/ 4

#### Explanation:

Rewite as (√7)/(√8) to make it easier
The goal here is to find a number that will get rid of the square root in bottom and the best way to do that is just to multiply the bottom by itself.
((√7)/(√8))*(√8)/(√8)
(√56)/(√64)
(√56)/8
Simplify root:
(√7*2*2*2)/8
It's a square so take out any numbers that have pairs like two of the $2 ' s$ and multiply the rest inside to make $14$
(2√14)/8

reduce
(√14)/ 4