Question

How do you rationalize the denominator of square root of 18 over square root of 3?

Answer 1

`sqrt(18)/sqrt(3)=sqrt(6)`

Explanation:

`sqrt(18)/sqrt(3)=(sqrt(9)sqrt(2))/sqrt(3)`

Then we rationalise the denominator.

`(sqrt(9)sqrt(2))/sqrt(3)xxsqrt(3)/sqrt(3)=(3sqrt(2)sqrt(3))/3`

Then we simplify

`(3sqrt(2)sqrt(3))/3=sqrt(2)sqrt(3)=sqrt(6)`

Hope this helps :)