# How do you rationalize the denominator of square root of 18 over square root of 3?

Oct 5, 2015

$\frac{\sqrt{18}}{\sqrt{3}} = \sqrt{6}$

#### Explanation:

$\frac{\sqrt{18}}{\sqrt{3}} = \frac{\sqrt{9} \sqrt{2}}{\sqrt{3}}$

Then we rationalise the denominator.

$\frac{\sqrt{9} \sqrt{2}}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{3 \sqrt{2} \sqrt{3}}{3}$

Then we simplify

$\frac{3 \sqrt{2} \sqrt{3}}{3} = \sqrt{2} \sqrt{3} = \sqrt{6}$

Hope this helps :)