# How do you rationalize the denominator (sqrt2)/(sqrt7+3)?

Multiply the numerator and the denominator by $\sqrt{7} - 3$ to have $\frac{\sqrt{14} - 3 \sqrt{2}}{7 - 9}$
=$\frac{\sqrt{14} - 3 \sqrt{2}}{- 2}$
=$\frac{3 \sqrt{2} - \sqrt{14}}{2}$