Question

How do you rewrite `2lnx+1/2lnu` as a single log?

Answer 1

I found: `ln(x^2sqrt(u))`

Explanation:

Here you can use two properties of the logs:
1] `alogx=logx^a`
2] `log_bx+log_by=log_b(x*y)` (same base!)

So, in your case you get:
`lnx^2+lnu^(1/2)=lnx^2+lnsqrt(u)=` same base:
`=ln(x^2sqrt(u))`